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## Core LaTeX auxiliary files
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*.cb2
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.*.lb
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*.bcf
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*.blg
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*-blx.aux
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*-blx.bib
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*.synctex(busy)
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*.synctex.gz(busy)
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## Build tool auxiliary files
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## Auxiliary and intermediate files from other packages
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# algorithms
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*.thm
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# beamer
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*.nav
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*.pre
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*.snm
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# uncomment this for glossaries-extra (will ignore makeindex's style files!)
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*.gnuplot
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*.table
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# Latexian
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TSWLatexianTemp*
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## Editors / OS junk
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*~
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## Generated PDF/output — comment these two lines out if you WANT to track the compiled PDF
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## latexmk
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## Other common temp files
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*.tmp
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*.log~
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249
ncr-of-monomial-curves.tex
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ncr-of-monomial-curves.tex
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\documentclass[10pt]{amsart}
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\usepackage[T1]{fontenc}
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\usepackage{mathtools}
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\usepackage{todonotes}
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\usepackage{blindtext}
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%\usepackage{parskip}
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\usepackage[
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backend=biber,
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style=alphabetic, % common in math; change if journal requires
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sorting=nyt,
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giveninits=true,
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eprint=false, url=false, doi=false, isbn=false,
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maxbibnames=9
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]{biblatex}
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\addbibresource{references.bib}
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\AtEveryBibitem{%
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\clearfield{month}%
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\clearfield{day}%
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\clearlist{language}%
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}
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\newtheorem{theorem}{Theorem}[section]
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\newtheorem{lemma}[theorem]{Lemma}
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\newtheorem{proposition}[theorem]{Proposition}
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\newtheorem{corollary}[theorem]{Corollary}
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\theoremstyle{definition}
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\newtheorem{definition}[theorem]{Definition}
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\newtheoremstyle{remstyle}
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{\medskipamount} % space above (half of standard topsep)
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{\medskipamount} % space below (half of standard topsep)
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{} % body font (normal/upright)
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{} % indent
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{\itshape} % head font (italic)
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{.} % punctuation after label
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{.5em} % space after label
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{} % head spec
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\theoremstyle{remstyle}
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\newtheorem{remark}[theorem]{Remark}
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\DeclareMathOperator{\supp}{supp}
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\DeclareMathOperator{\Frac}{Frac}
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\DeclareMathOperator{\spn}{span}
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\DeclareMathOperator{\Min}{Min}
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\DeclareMathOperator{\hgt}{ht}
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\DeclareMathOperator{\depth}{depth}
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\DeclareMathOperator{\gldim}{gl.dim}
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\DeclareMathOperator{\End}{End}
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\DeclareMathOperator{\id}{id}
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\newcommand{\qpower}[2][q]{{}^{#1}#2}
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\newcommand{\gapset}{\NN_0\setminus\SGR}
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\newcommand{\kk}{\mathsf{k}}
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\newcommand{\SGR}{\mathsf{S}}
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\newcommand{\NN}{\mathbb{N}}
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\newcommand{\ZZ}{\mathbb{Z}}
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\newcommand{\QQ}{\mathbb{Q}}
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\newcommand{\A}{\mathbb{A}}
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\title{Noncommutative Resolutions of Monomial Curves}
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\author{Markus M. R. Tripp}
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\date{}
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\begin{document}
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\maketitle
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\begin{abstract}
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\end{abstract}
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\section{Monomial curves}
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\section{Frobenius maps on affine semigroups}
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Let $\SGR$ be an affine semigroup, i.e., a finitely generated submonoid of $\ZZ^d$ for some $d \in \NN$, and let $R \coloneqq \kk[\SGR]$ denote the associated semigroup algebra. Fix a positive integer $q$, and write $q^{-1}\SGR \coloneqq \{ a/q \mid a \in \SGR \} \subseteq \QQ^d$ for the affine semigroup $\SGR$ refined by $q$. Consider the semigroup algebra
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\[ R^{1/q} \coloneqq \kk[q^{-1}\SGR] = \spn_\kk\{ x^{a/q} \mid a \in \SGR \} \]
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regarded as a subring of $\kk[\QQ^d] = \spn_\kk \{ x^\alpha \mid \alpha \in \QQ^d \}$, which carries a natural $\QQ^d$-grading. While the semigroup ring $R^{1/q}$ is defined for arbitrary $q \in \NN$ in any characteristic, the notation is motivated by the case $q = p^e$ with $\kk$ perfect of characteristic $p$, where $R^{1/q}$ is the ring of $q$-th roots of elements in $R = \kk[\SGR]$. Further, for $r = \sum_{a \in \QQ^d} k_a x^{a}$, we set $\qpower{r} \coloneqq \sum_{a \in \QQ^d} k_a x^{aq}$, and write $\qpower{F}$ for the resulting \emph{$q$-th pseudo-Frobenius endomorphism} on $R$, which maps $r$ to $\qpower{r}$.
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\begin{remark}
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% PREVIOUS VERSION % Note that even in positive characteristic $p$ with $q = p^e$, the $q$-th pseudo-Frobenius twist need not agree with the usual $q$-th Frobenius twist, where $R$-scalar multiplication is pulled back via the $e$-times iterated Frobenius endomorphism $F^e \colon r \mapsto r^{p^e}$ on $R$. The two agree precisely when the underlying field $\kk$ is finite, in which case $\kk \subseteq R$ is fixed pointwise by $F^e$.
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Note that even in positive characteristic $p$ with $q = p^e$, the $q$-th pseudo-Frobenius endomorphism $\qpower{F}$ need not agree with the usual $e$-times iterated Frobenius endomorphism $F^e \colon R \to R$, mapping $r$ to $r^{q}$ . The two agree precisely when the underlying field $\kk$ is finite, in which case $\kk \subseteq R$ is fixed pointwise by $F^e$.
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\end{remark}
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\begin{definition}
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Let $M$ be an $R$-module. The \textbf{$q$-th pseudo-Frobenius twist} of $M$, denoted $\qpower{M}$, is the $R$-module obtained by restricting scalars along the \mbox{$q$-th} pseudo-Frobenius endomorphism $\qpower{F}$. That is, $\qpower{M}$ is the $R$-module with the same underlying abelian group as $M$, but with $R$-action given by~$r\cdot m \coloneqq \qpower{r}m$
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% EXPLICIT DECLARATION % \[ \Bigl( \sum_{a \in S} k_a x^a \Bigr) \cdot_q \; m \coloneqq \bigl( \sum_{a \in S} k_a x^{aq} \bigr) m \]
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for all $r \in R$ and $m \in M$.
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\end{definition}
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\begin{lemma}
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There is a cannonical $R$-module isomorphism
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\[ R^{1/q} \xrightarrow{\;\sim\;} \qpower{R}, \]
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defined by $r = \sum_{a \in \SGR} k_a x^{a/q} \mapsto \qpower{r} = \sum_{a \in \SGR} k_a x^a$.
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\end{lemma}
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\begin{proof}
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By abuse of notation, we also write $\qpower{F}$ for the map $R^{1/q} \to \qpower{R}$ above; it is clearly additive and bijective. To verify compatibility with the respective $R$-module structures, write $r = \sum_{a \in \SGR} k_a x^a \in R$ and $f = \sum_{a \in \SGR} \ell_a x^{a/q} \in R^{1/q}$. Then
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\[ \qpower{F}(rf) = \qpower{F}\Bigl(\sum_{a, b \in \SGR} k_a\ell_b x^{a + b/q}\Bigr) = \sum_{a, b \in \SGR} k_a\ell_b x^{aq + b}, \]
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which is precisely $r\cdot\qpower{F}(f)$ in $\qpower{R}$.
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\end{proof}
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\begin{definition}
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We say that $R$ is \textbf{$q$-split} if the Frobenius map $\qpower{F} \colon R \to \qpower{R}$ splits as a map of $R$-modules. Moreover, we call $R$ \textbf{$q$-weakly normal} if, for every $r \in \kk[G(\SGR)]$\todo{$\Frac(R)$?}, $\qpower{r} \in R$ implies $r \in R$.
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\end{definition}
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\begin{remark}
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In semigroup-thereotic terms, $R = \kk[\SGR]$ is $q$-weakly normal if and only if, for every $a \in G(\SGR)$, $qa \in S$ implies $a \in S$. In particular, $\SGR$ (or equivalently, $R$) is normal if and only if $R$ is $q$-weakly normal for all $q \in \NN$.
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\end{remark}
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In positive characteristic $p$, the Frobenius endomorphism yields $\qpower[p]{r} \in R$ if and only if $r^p \in R$, from which we obtain the following:
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\begin{corollary}
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If $\kk$ has characteristic $p >0$, then $R$ is $p$-weakly normal
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% MORE INFORMATION % (or, equivalently, $p^e$-weakly normal for all $e \in \NN$)
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if and only if $R$ is weakly normal (i.e., for any $r \in \Frac(R)$, $r^p$ implies $r \in R$). In particular, $R$ is seminormal in this case.
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\end{corollary}
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\begin{proposition}\textnormal{\cite{Hochster1976}, \cite[Prop. 5.3]{Yasuda2009}}
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$R$ is $q$-split if and only if it is $q$-weakly normal.
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\end{proposition}
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\begin{proof}
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% FAKE PROOF % Suppose $R$ is $q$-split, with $\sigma \colon \qpower{R} \to R$ an $R$-module homomorphism satisfying $\sigma \circ \qpower{F} = \id_R$; in particular, $\sigma(1) = 1$. Now let $r \in \Frac(R)$ be such that $\qpower{r} \in R$. Then $r = r\sigma(1) = \sigma(\qpower{r}) \in R$.
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Suppose $R$ is $q$-split, with $\sigma \colon \qpower{R} \to R$ an $R$-module homomorphism satisfying $\sigma \circ \qpower{F} = \id_R$. Let $r \in \kk[G(\SGR)]$ be such that $\qpower{r} \in R$, and choose $s \in R^\bullet$ with $sr \in R$. Then
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\[ sr = \sigma\bigl( \qpower{F}(sr) \bigr) = \sigma(\qpower{s}\qpower{r}) = s\sigma(\qpower{r}), \]
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and cancelling $s$ yields $r = \sigma(\qpower{r}) \in R$.
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Conversely, suppose that $R$ is $q$-weakly normal. Let $\sigma \colon \qpower{R} \to R$ be the map that sends $f \in \qpower{R}$ to the unique $g \in R$ with $f = \qpower{g}$, if such a $g$ exists, and to $0$ otherwise. Clearly $\sigma \circ \qpower{F} = \id_R$, so it remains to show that $\sigma$ is a homomorphism of $R$-modules. As $\sigma$ is additive, it suffices to check that $\sigma(x^{aq+b}) = x^a \sigma(x^b)$ for $a$, $b \in \SGR$, which is straightforward using the assumption that $R$ is $q$-weakly normal. % MORE EXPLANATION % Suppose first that $b = qc$ for some $c \in \SGR$. Then $\sigma(x^{aq+b}) = \sigma(x^{q(a+c)}) = x^{a+c} = x^a \sigma(x^b)$. Now suppose there exists no $c \in \SGR$ with $b = qc$, so $\sigma(x^b) = 0$. If $aq+b = qc$ for some $c \in \SGR$, then $\qpower{x^{c-a}} = x^b \in R$, so $x^{c-a} \in R$ by assumption, giving $c-a \in \SGR$ and $b = q(c-a)$, a contradiction. Hence $\sigma(x^{aq+b}) = 0 = x^a\sigma(x^b)$.
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\end{proof}
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\begin{corollary}\textnormal{\cite[Cor. 6.3]{Bruns2006}}
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$R$ is normal if and only if $R$ is $q$-split for all $q \in \NN$.
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\end{corollary}
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\section{$R$-module decomposition of $R^{1/q}$}
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We now specialize to the case where $\SGR = \langle a_1, \dots, a_n \rangle \subseteq \NN_0$ is a numerical semigroup. Following Shibuta~\cite{Shibuta2017}, we sketch how $R^{1/q} = \kk[x^{a_1/q}, \dots, x^{a_n/q}]$ decomposes as an $R$-module. Observe that
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\[
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\Gamma_q \coloneqq \left\{ \bigl( x^{a_1/q} \bigr)^{e_1} \cdots \bigl( x^{a_n/q} \bigr)^{e_n} \mid e_i \in [0,q-1] \right\}
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\]
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is a homogeneous generating set for $R^{1/q}$. We partition $\Gamma_q$ by degree modulo $\ZZ$: writing each degree as
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$a/q$ with $a \in \NN_0$, this amounts to grouping elements by the residue of $a$ modulo $q$. This yields
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\[
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\Gamma_q = \Gamma_{q,0} \sqcup \Gamma_{q,1} \sqcup \cdots \sqcup \Gamma_{q,q-1},
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\]
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where $\Gamma_{q,r} \coloneqq \{ x^{a/q} \in \Gamma_q \mid a \equiv r \pmod{q}\}$. Let $I_{q,r}$ be the $R$-submodule of $\kk[x^q \mid q \in \QQ_{\geq 0}]$
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generated by $\Gamma_{q,r}$. As a $\kk$-vector space,
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\begin{equation}\label{eq:ind-summand-as-vector-space}
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I_{q,r} = \spn_\kk \{ x^{a/q} \mid a \in \SGR, \, a \equiv r \pmod{q} \},
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\end{equation}
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and, by construction, summing over $r$ gives the $R$-module decomposition
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\[
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R^{1/q} = \bigoplus_{r \in [0,q-1]} I_{q,r},
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\]
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where each summand is indecomposable (see Lemma~\ref{lemma:rank-1}).
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% REDUNDANT % \begin{lemma}
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%Each $R$-module $I_{q,r}$ has rank $1$ and is therefore indecomposable.
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%\end{lemma}
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%\begin{proof}
|
||||
%For simplicity, let $Q \coloneqq \Frac(R)$. The localization $V_{q,r} \coloneqq (R\setminus \{ 0 \})^{-1} I_{q,r}$ is isomorphic to $Q \otimes_R I_{q,r}$ as a $Q$-vector space. For a fixed element $x^{a/q} \in I_{q,r} \subseteq V_{q,r}$, we claim that $V_{q,r}$ is $1$-dimensional over $Q$, generated by $x^{a/q}$.
|
||||
|
||||
%To see this, take any $x^{b/q} \in I_{q,r}$. Since $b \equiv a \pmod{q}$, we have $b-a = cq$ for some $c \in \ZZ$. Thus, $x^{b/q} = x^c x^{a/q} \in \spn_Q\{ x^{a/q} \}$. The claim follows because any element of $V_{q,r}$ is a $Q$-linear combination of homogeneous elements of $I_{q,r}$.
|
||||
%\todo{note $\Frac{R} = \kk(x)$}
|
||||
%\end{proof}
|
||||
|
||||
Moreover, writing $m_{q,r}/q$ for the minimal degree occurring among
|
||||
elements of $\Gamma_{q,r}$, we have
|
||||
\[
|
||||
I_{q,r} = x^{m_{q,r}/q} \cdot \langle x^\alpha \mid \alpha \in \NN_0, \, m_{q,r}/q + \alpha \in \Gamma_{q,r} \rangle_R,
|
||||
\]
|
||||
from which it follows that every indecomposable summand of $R^{1/q}$ is isomorphic to $I(A) \coloneqq \langle x^\alpha \mid \alpha \in A \cup \{ 0 \} \rangle_R$ for some $A \subseteq \gapset$\todo{name?}. We may always choose $A$ to be minimal with respect to the order $\preceq_\SGR$ induced by $\SGR$, where $\alpha \preceq_\SGR \beta$ means $\beta - \alpha \in \SGR$. Write
|
||||
\[ \Min(\SGR) \coloneqq \{ A \in \gapset \mid A \text{ is minimal with respect to } \preceq_\SGR \}. \]
|
||||
In particular, as $q$ ranges over $\NN$, only finitely many indecomposable summands of $R^{1/q}$ occur, up to isomorphism.
|
||||
|
||||
\begin{lemma}\label{lemma:rank-1}
|
||||
For each $A \in \Min(\SGR)$, the $R$-module $I(A)$ has rank $1$ and is therefore indecomposable. Moreover, the assignment
|
||||
\[ A \mapsto [I(A)] \]
|
||||
defines a bijection between $\Min(\SGR)$ and the set of isomorphism classes of homogeneous $R$-submodules of $\bar{R} = \kk[x]$\todo{this also holds for $\kk[x,x^{-1}]$, interesting?}.
|
||||
\end{lemma}
|
||||
|
||||
\begin{proof}
|
||||
For simplicity, set $Q \coloneqq \Frac(R) = \kk(x)$\todo{note $\Frac{R} = \kk(x)$} and fix $A \in \Min(\SGR)$. Observe that $Q \otimes_R I(A)$ is naturally isomorphic, as a $Q$-vector space, to $I(A)_{(0)} \subseteq Q$. Since $I(A)$ contains $1$, it follows that $I(A)_{(0)} = Q$ and $I(A)$ has rank $1$.
|
||||
|
||||
For the second part, it is clear that $I(A)$, $A \in \Min(\SGR)$, are homogeneous fractional ideals of $R$, so the map is well-defined. To show injectivity, suppose we are given an $R$-module isomorphism $\varphi \colon I(A) \to I(B)$ for some $A$, $B \in \Min(\SGR)$. This induces an isomorphism of $Q$-vector spaces $\varphi_{(0)} \colon I(A)_{(0)} \to I(B)_{(0)}$, where both sides equal~$Q$.
|
||||
%and $\varphi_{(0)}(f/1) = \varphi(f)$ for all $f \in I(A)$.
|
||||
In particular, $\varphi_{(0)}$ (and therefore $\varphi$) is given by multiplication with some $g_0 \in Q$, so $\varphi(f) = g_0 f$ for all $f \in I(A)$. Taking $f=1$ yields $g_0 = \varphi(1) \in I(B)$. Since $\varphi$ is surjective and $1 \in I(B)$, a degree argument yields $g_0 \in \kk\setminus\{ 0 \}$. Consequently,
|
||||
\[ I(B) = \varphi(I(A)) = g_0 \cdot I(A) = I(A), \]
|
||||
and because $A$ and $B$ are both minimal with respect to $\preceq_\SGR$, it follows that~$A = B$. Now, let $I \subseteq \bar{R}$ be an arbitrary homogeneous $R$-submodule. Because $R$ is Noetherian and $\bar{R}$ is finitely generated as an $R$-module, $I$ is finitely generated, i.e, $I = \langle x^\beta \mid \beta \in B\rangle_R$ for some finite subset $B \subseteq \NN_0$. Define $m \coloneqq \min(B)$ and $A^\prime \coloneqq \{ \beta - m \mid \beta \in B \setminus \{ 0 \} \}$. Consequently, $I = x^m \cdot I(A^\prime)$, which implies that $I \cong I(A^\prime)$. The claim then follows from the fact that $I(A^\prime)=I(A)$, where $A$ denotes the set of minimal elements of $A^\prime \cap (\gapset)$ with respect to $\preceq_\SGR$.
|
||||
\end{proof}
|
||||
|
||||
\begin{remark}
|
||||
We now present another perspective on the $R$-modules $I(A)$. For $A \in \Min(\SGR)$, the $R$-module $I(A)$ admits the $\kk$-vector space description
|
||||
\[ I(A)=\spn_\kk \{x^\alpha \mid \alpha\in \SGR_A \}, \]
|
||||
where $\SGR_A\coloneqq (A \cup \{ 0 \}) +\SGR$. The set $\SGR_A$ is a normalized relative ideal of $\SGR$, that is, a subset of $\NN_0$ containing $0$ that is closed under addition by elements of $\SGR$. One readily checks that $A \mapsto \SGR_A$ defines a one-to-one correspondence between the elements of $\Min(\SGR)$ and the normalized relative ideals of $\SGR$.
|
||||
\todo{reference for this terminology?}
|
||||
\end{remark}
|
||||
|
||||
\begin{corollary}
|
||||
For each $A \in \Min(\SGR)$, the $R$-module $I(A)$ is maximal Cohen--Macaulay.
|
||||
\end{corollary}
|
||||
|
||||
\begin{proof}
|
||||
By the Cohen--Seidenberg theorems, $\dim(R) = \dim(\bar{R}) = \dim(\kk[x]) = 1$. Fix $A \in \Min(\SGR)$ and a maximal ideal $\mathfrak{m}$ of $R$. Since $R$ is a domain of Krull dimension $1$, every maximal ideal has height $1$; in particular $\dim(R_\mathfrak{m}) = \hgt(\mathfrak{m}) = 1$. The localization
|
||||
$I(A)_\mathfrak{m}$ is a non-zero $R_\mathfrak{m}$-submodule of $\kk(x)$, hence torsion-free, so $1 \leq \depth(I(A)_\mathfrak{m}) \leq \dim(R_\mathfrak{m}) = 1$. Hence, $I(A)$ is maximal Cohen--Macaulay.
|
||||
\end{proof}
|
||||
|
||||
\todo{add direct sums are Cohen--Macaulay (Bruns/Herzog, 1993, Prop. 1.2.9)}
|
||||
|
||||
\begin{lemma}
|
||||
It holds that $\qpower{\bar{R}} = \bar{R}^{\otimes q}$ as $R$-module.
|
||||
\end{lemma}
|
||||
|
||||
\begin{proof}
|
||||
Note that $\bar{R}^{1/q} = \kk[x^{1/q}] = \bigoplus_{r \in [0,q]} x^{r/q} \cdot \kk[x]$
|
||||
\end{proof}
|
||||
|
||||
%\begin{example}
|
||||
%\end{example}
|
||||
|
||||
\begin{proposition}
|
||||
For sufficiently large $q$, all indecomposable summands of $R^{1/q}$ are isomorphic to the normalization $\bar{R} = \kk[x]$ of $R$. That is, $R^{1/q} \cong \bar{R}^{\oplus q}$.
|
||||
\end{proposition}
|
||||
|
||||
\begin{proof}
|
||||
Let $q$ be such that $\ZZ_{\geq q} \subseteq S$, and fix $r \in [0,q-1]$. For simplicity, set
|
||||
\[ \supp(I_{q,r}) \coloneqq \{ a/q \mid a \in S, \, a \equiv r \pmod{q} \} \]
|
||||
and observe that $\supp(I_{q,r}) \subseteq \{ m_{q,r}/q + n \mid n \in \NN_0\}$, where $m_{q,r}/q$ is the minimum of $\supp(I_{q,r})$. Conversely, for each $n \in \NN_0$, the choice of $q$ ensures $nq \in S$, and hence $m_{q,r} + nq \in S$. Since $m_{q,r}+nq \equiv r \pmod q$, we
|
||||
obtain $m_{q,r}/q + n \in \supp(I_{q,r})$, and altogether
|
||||
\[ \supp(I_{q,r}) = \{ m_{q,r}/q + n \mid n \in \NN_0\}. \]
|
||||
It now follows from~\eqref{eq:ind-summand-as-vector-space} that
|
||||
\[ I_{q,r} = \spn_\kk \{ x^{m_{q,r}/q + n} \mid n \in \NN_0 \} = x^{m_{q,r}/q} \cdot \spn_\kk\{ x^n \mid n \in \NN_0 \} \cong k[x] . \]
|
||||
\end{proof}
|
||||
|
||||
%\begin{proposition}
|
||||
% R is not q-split
|
||||
%\end{proposition}
|
||||
|
||||
%\begin{proposition}
|
||||
% if two consecutive powers have same indecomposable summands, then so do all larger powers
|
||||
%\end{proposition}
|
||||
|
||||
\section{Global dimension of endomorphism algebras}
|
||||
|
||||
\todo[inline]{For $\A \coloneqq \oplus_{A \in \Min(S)} I(A)$, think about $\gldim(\End_R(\A))$ and/or $\gldim(\End_R(R^{1/q}))$ for small $q$.}
|
||||
|
||||
\printbibliography
|
||||
|
||||
\end{document}
|
||||
59
references.bib
Normal file
59
references.bib
Normal file
|
|
@ -0,0 +1,59 @@
|
|||
@article{Shibuta2017,
|
||||
title = {Affine semigroup rings are of finite F-representation type},
|
||||
volume = {45},
|
||||
issn = {0092-7872, 1532-4125},
|
||||
url = {https://www.tandfonline.com/doi/full/10.1080/00927872.2017.1313425},
|
||||
doi = {10.1080/00927872.2017.1313425},
|
||||
pages = {5465--5470},
|
||||
number = {12},
|
||||
journaltitle = {Communications in Algebra},
|
||||
shortjournal = {Communications in Algebra},
|
||||
author = {Shibuta, Takafumi},
|
||||
urldate = {2026-08-03},
|
||||
date = {2017-12-02},
|
||||
langid = {english},
|
||||
}
|
||||
|
||||
@article{Hochster1976,
|
||||
title = {The purity of the Frobenius and local cohomology},
|
||||
journal = {Advances in Mathematics},
|
||||
volume = {21},
|
||||
number = {2},
|
||||
pages = {117-172},
|
||||
year = {1976},
|
||||
issn = {0001-8708},
|
||||
doi = {https://doi.org/10.1016/0001-8708(76)90073-6},
|
||||
url = {https://www.sciencedirect.com/science/article/pii/0001870876900736},
|
||||
author = {Melvin Hochster and Joel L Roberts}
|
||||
}
|
||||
|
||||
@article{Yasuda2009,
|
||||
title = {On monotonicity of F-blowup sequences},
|
||||
volume = {53},
|
||||
issn = {0019-2082},
|
||||
url = {https://projecteuclid.org/journals/illinois-journal-of-mathematics/volume-53/issue-1/On-monotonicity-of-F-blowup-sequences/10.1215/ijm/1264170841.full},
|
||||
doi = {10.1215/ijm/1264170841},
|
||||
number = {1},
|
||||
journaltitle = {Illinois Journal of Mathematics},
|
||||
shortjournal = {Illinois J. Math.},
|
||||
author = {Yasuda, Takehiko},
|
||||
urldate = {2026-08-11},
|
||||
date = {2009-01-01},
|
||||
}
|
||||
|
||||
@article{Bruns2006,
|
||||
title = {On seminormal monoid rings},
|
||||
volume = {302},
|
||||
rights = {https://www.elsevier.com/tdm/userlicense/1.0/},
|
||||
issn = {00218693},
|
||||
url = {https://linkinghub.elsevier.com/retrieve/pii/S0021869305006605},
|
||||
doi = {10.1016/j.jalgebra.2005.11.012},
|
||||
pages = {361--386},
|
||||
number = {1},
|
||||
journaltitle = {Journal of Algebra},
|
||||
shortjournal = {Journal of Algebra},
|
||||
author = {Bruns, Winfried and Li, Ping and Römer, Tim},
|
||||
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|
||||
date = {2006-08},
|
||||
langid = {english},
|
||||
}
|
||||
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Reference in a new issue